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Education

Published: 30th April 2019     

NTA declares JEE Main 2019 results, 24 obtain a score of 100: Check cut off here

This was the first JEE Main conducted by the NTA, after the agency was set up in June 2018. What's next for the students? 

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JEE MAIN 2019

The exam was held in two phases

The National Testing Agency (NTA) declared the Joint Entrance Examination - Main Paper I 2019 results. Of the 11,47,125 candidates who wrote the examinations in two phases (January and April), 24 obtained a score of 100. Unlike previous years, this year the candidates were given an option of appearing for the exams twice and the best of the two scores was considered for ranks.

This year's exam was also the first to be conducted by the newly set up NTA, The agency in a release says that of the 6,08,440 candidates who appeared for the exams in both the months, 2,97,932 have improved their performance. The final answer keys of Paper-I are available on the JEE (Main) website www.jeemain.nic.in.

The first examination was held from January 8 to 12 in two shifts and the second was held on April 7, 8, 9, 10 and 12. The NTA said that the examination rank list was prepared based on a normalisation procedure, to ensure that candidates are neither benefitted nor disadvantaged due to different question papers. The percentile scores were calculated up to 7 decimal places.  

A total of 3,30,702 women, 8,16,420 men and three transgenders appeared for the examination this year. Also, this was the first time that reservations were given to the new EWS category candidates. 

Formerly known as the All India Engineering Entrance Examination (AIEEE), JEE-Main is a national level entrance examination for admission to institutes that include the National Institutes of Technology and the Indian Institute of Information Technology.

Cut off for General category was set at 89.7548849 while the EWS students had a cut off of 78.2174869. OBC, SC and ST candidates had to clear cut off of 74.3166557, 54.0128155 and 44.3345172 respectively and People with Disability had a cut off of 0.1137173 for the NTA Score for JEE (Advanced)-2019 based on Paper-I.


IIT Roorkee, which will conduct the Joint Entrance Examination (Advanced) this year, has said that the top 2.45 lakh candidates from the JEE (Main) would be eligible for the JEE (Advanced) this year. 


The IITs, earlier this month, had offered, on average, 500 seats to candidates from the economically weaker sections from the 2019-’20 academic year. IIT Madras had said that they will introduce 4 per cent quota for the EWS category this academic year. “This will throw infrastructural challenges, but it is doable,” Director Baskar Ramamurthi told the media. “Classrooms will not be much of a problem but accommodations have to be worked out.” Officials at IIT-Kharagpur also said the college may reserve 3 per cent seats for EWS candidates. However, they added that infrastructure problems will arise when a fresh batch of students would have to be accommodated in the second year of the implementation of the scheme.

One can check their results at www.jeemain.nic.in

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Education students NIT exam iit JEE Results EWS NTA AIEEE ranks
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